Optimal. Leaf size=60 \[ -\frac{1}{4 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{\tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{1}{4 d (a \sin (c+d x)+a)^2} \]
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Rubi [A] time = 0.0582109, antiderivative size = 60, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {2667, 44, 206} \[ -\frac{1}{4 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{\tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{1}{4 d (a \sin (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 2667
Rule 44
Rule 206
Rubi steps
\begin{align*} \int \frac{\sec (c+d x)}{(a+a \sin (c+d x))^2} \, dx &=\frac{a \operatorname{Subst}\left (\int \frac{1}{(a-x) (a+x)^3} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a \operatorname{Subst}\left (\int \left (\frac{1}{2 a (a+x)^3}+\frac{1}{4 a^2 (a+x)^2}+\frac{1}{4 a^2 \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{1}{4 d (a+a \sin (c+d x))^2}-\frac{1}{4 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{4 a d}\\ &=\frac{\tanh ^{-1}(\sin (c+d x))}{4 a^2 d}-\frac{1}{4 d (a+a \sin (c+d x))^2}-\frac{1}{4 d \left (a^2+a^2 \sin (c+d x)\right )}\\ \end{align*}
Mathematica [A] time = 0.0923803, size = 38, normalized size = 0.63 \[ \frac{\tanh ^{-1}(\sin (c+d x))-\frac{\sin (c+d x)+2}{(\sin (c+d x)+1)^2}}{4 a^2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.071, size = 72, normalized size = 1.2 \begin{align*} -{\frac{\ln \left ( \sin \left ( dx+c \right ) -1 \right ) }{8\,d{a}^{2}}}-{\frac{1}{4\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{1}{4\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) }}+{\frac{\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{8\,d{a}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.963566, size = 97, normalized size = 1.62 \begin{align*} -\frac{\frac{2 \,{\left (\sin \left (d x + c\right ) + 2\right )}}{a^{2} \sin \left (d x + c\right )^{2} + 2 \, a^{2} \sin \left (d x + c\right ) + a^{2}} - \frac{\log \left (\sin \left (d x + c\right ) + 1\right )}{a^{2}} + \frac{\log \left (\sin \left (d x + c\right ) - 1\right )}{a^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.08026, size = 279, normalized size = 4.65 \begin{align*} \frac{{\left (\cos \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right ) - 2\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (\cos \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right ) - 2\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, \sin \left (d x + c\right ) + 4}{8 \,{\left (a^{2} d \cos \left (d x + c\right )^{2} - 2 \, a^{2} d \sin \left (d x + c\right ) - 2 \, a^{2} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\sec{\left (c + d x \right )}}{\sin ^{2}{\left (c + d x \right )} + 2 \sin{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.18831, size = 96, normalized size = 1.6 \begin{align*} \frac{\frac{2 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a^{2}} - \frac{2 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a^{2}} - \frac{3 \, \sin \left (d x + c\right )^{2} + 10 \, \sin \left (d x + c\right ) + 11}{a^{2}{\left (\sin \left (d x + c\right ) + 1\right )}^{2}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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